| ⇦ | 
| ⇨ |
On bombarding U²³⁵ by slow neutron, 200 MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be
Options
(a) 8×10¹⁶/s
(b) 20×10¹⁶/s
(c) 5×10²²/s
(d) 5×10¹⁶/s
Correct Answer:
5×10¹⁶/s
Explanation:
Energy released per fission of uranium = 200 × 10⁶ × 1 × 10⁻¹⁹ J
Power output = 1.6 × 10⁶ W
Number of fission /s = 1.6 × 10⁶ / 200 × 10⁶ × 1 × 10⁻¹⁹ = 5 × 10¹⁶ /s
This is the rate of fission.
Related Questions: - The electric vector vibration of an electromagnetic wave is given by
- The concentric spheres of radii R and r have positive charges q₁ and q₂ with equal
- A car moving with a velocity of 36 km/hr crosses a siren of frequency 500 Hz.
- Core of electromagnets are made of ferromagnetic material which has
- A radioactive substance contains 10000 nuclei and its halflife period is 20 days
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The electric vector vibration of an electromagnetic wave is given by
- The concentric spheres of radii R and r have positive charges q₁ and q₂ with equal
- A car moving with a velocity of 36 km/hr crosses a siren of frequency 500 Hz.
- Core of electromagnets are made of ferromagnetic material which has
- A radioactive substance contains 10000 nuclei and its halflife period is 20 days
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply