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On bombarding U²³⁵ by slow neutron, 200 MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be
Options
(a) 8×10¹⁶/s
(b) 20×10¹⁶/s
(c) 5×10²²/s
(d) 5×10¹⁶/s
Correct Answer:
5×10¹⁶/s
Explanation:
Energy released per fission of uranium = 200 × 10⁶ × 1 × 10⁻¹⁹ J
Power output = 1.6 × 10⁶ W
Number of fission /s = 1.6 × 10⁶ / 200 × 10⁶ × 1 × 10⁻¹⁹ = 5 × 10¹⁶ /s
This is the rate of fission.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a transistor the collector current is always less than the emitter current
- The specific charge of a proton is 9.6×10⁷ C/kg. The specific charge of an alpha particle
- When indensity of radiation is increased on a photosensitive plate, then
- Water falls from a height of 60m at the rate of 15 kg/s to operate a turbine
- A spring gun of spring constant 90 N/cm is compressed 12 cm by a ball of mass
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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