| ⇦ | 
| ⇨ |
On bombarding U²³⁵ by slow neutron, 200 MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be
Options
(a) 8×10¹⁶/s
(b) 20×10¹⁶/s
(c) 5×10²²/s
(d) 5×10¹⁶/s
Correct Answer:
5×10¹⁶/s
Explanation:
Energy released per fission of uranium = 200 × 10⁶ × 1 × 10⁻¹⁹ J
Power output = 1.6 × 10⁶ W
Number of fission /s = 1.6 × 10⁶ / 200 × 10⁶ × 1 × 10⁻¹⁹ = 5 × 10¹⁶ /s
This is the rate of fission.
Related Questions: - When a light beam of frequency v is incident on a metal surface,
- If in a L-R series circuit the power factor is 1/2 and R=100Ω, then the value of L is,
- A transistor-oscillator using a resonant circuit with an inductor L
- A hemispherical bowl of radius R is rotating about its axis of symmetry
- The difference in the variation of resistance with temperature in a metal
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a light beam of frequency v is incident on a metal surface,
- If in a L-R series circuit the power factor is 1/2 and R=100Ω, then the value of L is,
- A transistor-oscillator using a resonant circuit with an inductor L
- A hemispherical bowl of radius R is rotating about its axis of symmetry
- The difference in the variation of resistance with temperature in a metal
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply