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On bombarding U²³⁵ by slow neutron, 200 MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be
Options
(a) 8×10¹⁶/s
(b) 20×10¹⁶/s
(c) 5×10²²/s
(d) 5×10¹⁶/s
Correct Answer:
5×10¹⁶/s
Explanation:
Energy released per fission of uranium = 200 × 10⁶ × 1 × 10⁻¹⁹ J
Power output = 1.6 × 10⁶ W
Number of fission /s = 1.6 × 10⁶ / 200 × 10⁶ × 1 × 10⁻¹⁹ = 5 × 10¹⁶ /s
This is the rate of fission.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Sodium has body centred packing. Distance between two nearest atoms is 3.7 Å.
- A capacitor having a capacity of 2 μF is charged to 200V and then the plates
- A proton is moving in a uniform magnetic field B in a circular path of radius a
- Two bodies A and B having temperature 327° C and 427° C are radiating heat
- In a pure capacitive A.C circuit, current and voltage differ in phase by
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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