| ⇦ | 
| ⇨ |
In Young’s double slit experiment, the fringe width is 1×10⁻⁴ m, if the distance between the slit and screen is doubled and the distance between two slits is reduced to half and the wavelength is changed from 6.4×10⁻⁷ m to 4.0×10⁻⁷ m, then the value of new fringe width will be
Options
(a) 2.5×10⁻⁴ m
(b) 2.0×10⁻⁴ m
(c) 1×10⁻⁴ m
(d) 0.5×10⁻⁴ m
Correct Answer:
2.5×10⁻⁴ m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two 220V – 100W bulbs are connected first in series and then in parallel.
- In Young’s double slit experiment, the wavelength of the light used is doubled
- The half life of radioactive isotope ‘X’ is 50 years. It decays to
- If oxygen has root mean square velocity of C m/s, then root mean square velocity of H
- In some region, gravitational field is zero. The gravitational potential
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two 220V – 100W bulbs are connected first in series and then in parallel.
- In Young’s double slit experiment, the wavelength of the light used is doubled
- The half life of radioactive isotope ‘X’ is 50 years. It decays to
- If oxygen has root mean square velocity of C m/s, then root mean square velocity of H
- In some region, gravitational field is zero. The gravitational potential
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply