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In Young’s double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduces to half. As a result the fringe width
Options
(a) is doubled
(b) is halved
(c) becomes four times
(d) remains unchanged
Correct Answer:
becomes four times
Explanation:
Fringe width β = Dλ/d;
From qn D’ = 2D and d’ = d/2
β’ = λD¹ / d¹ = 4β
