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In which of the following reaction standard entropy change (ΔS⁰) is positive and standard Gibb’s energy change (ΔG⁰) decreases sharply with increasing temperature
Options
(a) C (graphite) + 1/2 O₂(g) → CO(g)
(b) CO(g) + 1/2 O₂(g) → CO₂(g)
(c) Mg(s) + 1/2 O₂(g) → MgO(s)
(d) 1/2 C(graphite) + 1/2 O₂(g) → 1/2 CO₂(g)
Correct Answer:
C (graphite) + 1/2 O₂(g) → CO(g)
Explanation:
C(graphite) + 1/2 O₂(g) → CO(g),
Δn(g) = 1 – 1/2 = 1/2,
As amount of gaseous substance is increasing in product, thus
ΔS is positive for this reaction. And we know that ΔG = ΔH -TΔS. As ΔS is positive, thus increase in temperature will make TΔS more negative and ΔG will decrease.
Related Questions: - Pyridine is less basic than triethylamine because
- Ratio of Cᵥ and Cᵥ of the gas X is 1.4. The number of atoms of the gas X present
- Which of the following is the monoliquid propellant
- Which is most base
- Bohr’s theory was modified to give the concept of elliptical orbits by
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Pyridine is less basic than triethylamine because
- Ratio of Cᵥ and Cᵥ of the gas X is 1.4. The number of atoms of the gas X present
- Which of the following is the monoliquid propellant
- Which is most base
- Bohr’s theory was modified to give the concept of elliptical orbits by
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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