⇦ | ⇨ |
In which of the following compounds, nitrogen exhibits highest oxidation state
Options
(a) N₂H₄
(b) NH₃
(c) N₃H
(d) NH₂OH
Correct Answer:
N₃H
Explanation:
N₂H₄ ⇒ 2x + 4 (+1) = 0 ⇒ 2x + 4 = 0 ⇒ x = x -2. NH₃ ⇒ x + 3 (+1) = 0, ⇒ x = -3. N₃H ⇒ 3x + 1(+1) = 0 ⇒ 3x + 1 = 0. ⇒ x = -1/3. NH₂OH ⇒ x + 2 + 1(-2) + 1 = 0 ⇒ x + 1 = 0. ⇒ x = -1. Thus , highest oxidation state is -1/3.
Related Questions: - Among the following, identify the compound which cannot act as both oxidising
- Allyl chloride on dehydrochlorination gives
- To prepare a pure sample on n-hexane using sodium metal as one reactant, the
- The solubility of CuBr is 2 ˣ 10⁻⁴ mol/L at 25⁰C. The Ksp value for CuBr is
- Oxidation state of sulphur in S₈, H₂S and S₂F₂ is
Topics: P Block Elements in Group 15
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Among the following, identify the compound which cannot act as both oxidising
- Allyl chloride on dehydrochlorination gives
- To prepare a pure sample on n-hexane using sodium metal as one reactant, the
- The solubility of CuBr is 2 ˣ 10⁻⁴ mol/L at 25⁰C. The Ksp value for CuBr is
- Oxidation state of sulphur in S₈, H₂S and S₂F₂ is
Topics: P Block Elements in Group 15 (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply