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In which of the following compounds, nitrogen exhibits highest oxidation state
Options
(a) N₂H₄
(b) NH₃
(c) N₃H
(d) NH₂OH
Correct Answer:
N₃H
Explanation:
N₂H₄ ⇒ 2x + 4 (+1) = 0 ⇒ 2x + 4 = 0 ⇒ x = x -2. NH₃ ⇒ x + 3 (+1) = 0, ⇒ x = -3. N₃H ⇒ 3x + 1(+1) = 0 ⇒ 3x + 1 = 0. ⇒ x = -1/3. NH₂OH ⇒ x + 2 + 1(-2) + 1 = 0 ⇒ x + 1 = 0. ⇒ x = -1. Thus , highest oxidation state is -1/3.
Related Questions: - The hybridisation of C₂H₂ is
- Calcination is used in metallurgy to remove
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- The oxidation state of Fe in brown ring complex [Fe(H₂O)₅NO]SO₄ is
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Topics: P Block Elements in Group 15
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The hybridisation of C₂H₂ is
- Calcination is used in metallurgy to remove
- How many edta molecules can surround calcium
- The oxidation state of Fe in brown ring complex [Fe(H₂O)₅NO]SO₄ is
- Shape-selective catalysis is a reaction catalysed by
Topics: P Block Elements in Group 15 (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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