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In which of the following compounds, nitrogen exhibits highest oxidation state
Options
(a) N₂H₄
(b) NH₃
(c) N₃H
(d) NH₂OH
Correct Answer:
N₃H
Explanation:
N₂H₄ ⇒ 2x + 4 (+1) = 0 ⇒ 2x + 4 = 0 ⇒ x = x -2. NH₃ ⇒ x + 3 (+1) = 0, ⇒ x = -3. N₃H ⇒ 3x + 1(+1) = 0 ⇒ 3x + 1 = 0. ⇒ x = -1/3. NH₂OH ⇒ x + 2 + 1(-2) + 1 = 0 ⇒ x + 1 = 0. ⇒ x = -1. Thus , highest oxidation state is -1/3.
Related Questions: - A helium, molecule is two times heavier than a hydrogen molecule at 298 K
- Non – lanthanide element is
- What is the maximum number of orbitals that can be identified with the following
- Which one of the following statements is incorrect with regard to ortho and para
- Which of the following is the strongest base
Topics: P Block Elements in Group 15
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A helium, molecule is two times heavier than a hydrogen molecule at 298 K
- Non – lanthanide element is
- What is the maximum number of orbitals that can be identified with the following
- Which one of the following statements is incorrect with regard to ortho and para
- Which of the following is the strongest base
Topics: P Block Elements in Group 15 (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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