In the reaction : 2N₂O₅ → 4NO₂ + O₂, initial pressure is 500 atm and rate

In The Reaction 2no 4no O Initial Chemistry Question

In the reaction : 2N₂O₅ → 4NO₂ + O₂, initial pressure is 500 atm and rate constant k is 3.38 ˣ 10⁻⁵ s⁻¹.After 10 minutes the final pressure of N₂O₅ is

Options

(a) 490 atm
(b) 250 atm
(c) 480 atm
(d) 420 atm

Correct Answer:

490 atm

Explanation:

P₀ = 500 atm. k = 2.303 / t log₁₀ p₀ / p(t), 3.38 ⨯ 10⁻⁵ = 2.303 / 10⨯60 log 500/ p(t) or, 0.00880 = log 500 / p(t) ⇒ 500 / 1.02 = 490 atm.

Related Questions:

  1. Which of the following statement about the member of any one homologous series
  2. In a cubic cell,the contribution of an atom at a face of the unit cell is
  3. An organic compound contains 40%C, 6.66% H and rest oxygen .its vapour density
  4. Which is the correct order of increasing energy of the listed orbitals in the atom
  5. A primary alcohol,C₃H₈O (A) on heating with sulphuric acid undergo dehydration

Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*