| ⇦ | 
| ⇨ |
In the following change,KMnO₄ → MnO₂, the oxidation state of Mn changes as
Options
(a) 7 → 4
(b) 5 → 2
(c) 7 → 5
(d) 3 → 7
Correct Answer:
7 → 4
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If we want to study relative arrangement of atoms in a molecule we study
- The percentage weight of Zn in white vitriol [ZnSO₄ 7H₂O] is approximately equal
- Maximum number of H-bonds in one molecule of water is
- Change in enthalpy for reaction,2H₂O₂ → 2H₂O + O₂
- The angular momentum of electron in ‘d’ orbital is equal to
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If we want to study relative arrangement of atoms in a molecule we study
- The percentage weight of Zn in white vitriol [ZnSO₄ 7H₂O] is approximately equal
- Maximum number of H-bonds in one molecule of water is
- Change in enthalpy for reaction,2H₂O₂ → 2H₂O + O₂
- The angular momentum of electron in ‘d’ orbital is equal to
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply