| ⇦ | 
| ⇨ |
In P-N junction having depletion layer of thickness 10⁻⁶ m, the potential across it is 0.1 V. The electric field is
Options
(a) 10⁷
(b) 10⁻⁶
(c) 10⁵
(d) 10⁻⁵
Correct Answer:
10⁵
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Light of wavelength λ is incident on slit of width d. The resulting diffraction
- An objective moves ,starting from rest through a resistive medium
- A charge of 100 μC has a potential at a distance of 9 m is
- A round uniform body of radius R, mass M and moment of inertia I rolls down
- Sound waves travel at 350m/s through a warm air and at 3500 m/s through brass
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Light of wavelength λ is incident on slit of width d. The resulting diffraction
- An objective moves ,starting from rest through a resistive medium
- A charge of 100 μC has a potential at a distance of 9 m is
- A round uniform body of radius R, mass M and moment of inertia I rolls down
- Sound waves travel at 350m/s through a warm air and at 3500 m/s through brass
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
As we know;
|dV|=E.d
dV-> barrier voltage
E-> barrier field
d-> depletion region
So, E = 0.1V/10^-6m
E = 10^5 V/m