| ⇦ |
| ⇨ |
In HS⁻, I⁻, R-NH₂, NH₃ order of proton accepting tendency will be
Options
(a) I⁻ > NH₃ > R-NH₂ > HS⁻
(b) NH₃ > R-NH₂ > HS⁻ > I⁻
(c) R-NH₂ > NH₃ > HS⁻ > I⁻
(d) HS⁻ > R-NH₂ > NH₃ > I⁻
Correct Answer:
R-NH₂ > NH₃ > HS⁻ > I⁻
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The correct statement regarding defects in crystalline solids is
- When sodium bicarbonate is heated strongly for calcined in a Kiln, it forms
- The number of electrons involved in the reduction of one nitrate ion
- When iodine is dissolved in CCl₄, the resulting colour is
- Which of the following does not acts as Lewis acid
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The correct statement regarding defects in crystalline solids is
- When sodium bicarbonate is heated strongly for calcined in a Kiln, it forms
- The number of electrons involved in the reduction of one nitrate ion
- When iodine is dissolved in CCl₄, the resulting colour is
- Which of the following does not acts as Lewis acid
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply