| ⇦ |
| ⇨ |
In Cu-ammonia complex, the state of hybridization of Cu²⁺ is
Options
(a) sp³
(b) d³
(c) sp²f
(d) dsp²
Correct Answer:
dsp²
Explanation:
Square planar complex is formed by dsp² hybridisation.
Related Questions: - Which of the following is paramagnetic
- In the periodic table from left to right in a period,the atomic volume
- An open system
- Which is weakest acid
- The oxidation state of nitrogen is highest in
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is paramagnetic
- In the periodic table from left to right in a period,the atomic volume
- An open system
- Which is weakest acid
- The oxidation state of nitrogen is highest in
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply