| ⇦ | 
| ⇨ |
In Cr₂O₇²⁻ the oxidation numbers are
Options
(a) O = -2, Cr = +6
(b) O = +2, Cr = -6
(c) O = -7, Cr = +6
(d) none of these
Correct Answer:
O = -2, Cr = +6
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The limiting radius ratio for tetrahedral shape is
- If HNO₃ changes into N₂O, the oxidation number is changed by
- Main constituents of LPG is
- Among the following the least thermally stable is
- The process used for the extraction of sodium is called
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The limiting radius ratio for tetrahedral shape is
- If HNO₃ changes into N₂O, the oxidation number is changed by
- Main constituents of LPG is
- Among the following the least thermally stable is
- The process used for the extraction of sodium is called
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply