In an ac circuit an alternating voltage e = 200 √2 sin 100 t volts is connected

In an ac circuit an alternating voltage e = 200 √2 sin 100 t volts is connected to a capacitor of capacity 1 µF. The r.m.s. value of the current in the circuit is

Options

(a) 10 mA
(b) 100 mA
(c) 200 mA
(d) 20 mA

Correct Answer:

20 mA

Explanation:

Vᵣₘₛ = 200 √2 / √2 = 200 V
Iᵣₘₛ = Vᵣₘₛ / Xc = 200/1 / 100 x 10⁻⁶
= 2 x 10⁻² = 20 mA

admin:

View Comments (2)

Related Questions

  1. The surface tension of a liquid is 5 newton per metre. If a film
  2. The power obtained in a reactor using U²³⁵ disintegration is 1000 kW
  3. The angle between the dipole moment and electric field at any point on the equatoria
  4. The net electric force on a charge of +3μC at the mid-point on the line joining two
  5. Heat produced in a resistance according to which law?