| ⇦ | 
| ⇨ |
In an a.c circuit the e.m.f. (e) and the current (i) at any instant are given respectively by
e = E₀ sin ?t
i = I₀ sin (?t – ?)
The average power in the circuit over one cycle of a.c. is
Options
(a) E₀I₀ / 2
(b) E₀I₀ / 2 sin ?
(c) E₀I₀ / 2 cos ?
(d) E₀I₀
Correct Answer:
E₀I₀ / 2 cos ?
Explanation:
The average power in the circuit over one cycle of a.c. is given by
Pₐᵥ = eᵣₘₛ x iᵣₘₛ x cos ?
= E₀ / √2 x I₀ / √2 x cos ? = E₀I₀ / 2 cos ?
Related Questions: - Unit of reduction factor is
- The total energy of a particle executing SHM is 80 J
- A toroid having 200 turns carries a current of 1 A. The average radius of the toroid
- Two charged particles have charges and masses in the ratio 2:3 and 1:4 respectively.
- Number of electrons in one mC charge, given e=1.6×10⁻¹⁹ C, will be
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Unit of reduction factor is
- The total energy of a particle executing SHM is 80 J
- A toroid having 200 turns carries a current of 1 A. The average radius of the toroid
- Two charged particles have charges and masses in the ratio 2:3 and 1:4 respectively.
- Number of electrons in one mC charge, given e=1.6×10⁻¹⁹ C, will be
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply