| ⇦ | 
| ⇨ |
In a potentiometer experiment two cells of e.m.f. E₁ and E₂ are used in series and in conjunction and the balancing length is found to be 58 cm of the wire. If the polarity of E₂ is reversed, then the balancing length becomes 29 cm. The ratio of e.m.f. of the two cells E₁/E₂ is
Options
(a) (1:1)
(b) (2:1)
(c) (3:1)
(d) (4:1)
Correct Answer:
(3:1)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A L-C-R circuit with L=1.00 mH, C=10μF and R=50Ω, is driven with 5 V AC voltage.
- The input resistance of a silicon transistor is 100 W. Base current is changed
- A single slit Fraunhogger diffraction pattern is formed with white light.
- A electric dipole is placed at an angle of 30⁰ to a non-uniform electric field.
- In cyclotron, for a given magnet, radius of the semicircle traced by positive ion
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A L-C-R circuit with L=1.00 mH, C=10μF and R=50Ω, is driven with 5 V AC voltage.
- The input resistance of a silicon transistor is 100 W. Base current is changed
- A single slit Fraunhogger diffraction pattern is formed with white light.
- A electric dipole is placed at an angle of 30⁰ to a non-uniform electric field.
- In cyclotron, for a given magnet, radius of the semicircle traced by positive ion
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply