| ⇦ | 
| ⇨ |
In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second is 4×10²⁰. If the energy released per fission is 250 MeV, then the total energy released in 10 h is (1 eV=1.6×10⁻¹⁹ J)
Options
(a) 576×10⁶ J
(b) 576×10¹² J
(c) 576×10¹⁵ J
(d) 576×10¹⁸ J
Correct Answer:
576×10¹² J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Identify the pair whose dimensions are equal
- The necessary condition in making of a junction transistor
- A ball is thrown vertically downwards from a height of 20 m with an initially
- The control rods used in a nuclear reactor can be made up of
- Two particles A and B having equal charges, after being accelerated
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Identify the pair whose dimensions are equal
- The necessary condition in making of a junction transistor
- A ball is thrown vertically downwards from a height of 20 m with an initially
- The control rods used in a nuclear reactor can be made up of
- Two particles A and B having equal charges, after being accelerated
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply