| ⇦ | 
| ⇨ |
In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second is 4×10²⁰. If the energy released per fission is 250 MeV, then the total energy released in 10 h is (1 eV=1.6×10⁻¹⁹ J)
Options
(a) 576×10⁶ J
(b) 576×10¹² J
(c) 576×10¹⁵ J
(d) 576×10¹⁸ J
Correct Answer:
576×10¹² J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - For the action of a common Base (CB) transistor, (E=emitter, B= base, C= collector)
- A source and an observer approach each other with same velocity 50 m/s. If the frequency
- The fluctuation in the input voltage of 200 V to a domestic circuit is +10V
- Dimensions of electrical resistance are
- A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For the action of a common Base (CB) transistor, (E=emitter, B= base, C= collector)
- A source and an observer approach each other with same velocity 50 m/s. If the frequency
- The fluctuation in the input voltage of 200 V to a domestic circuit is +10V
- Dimensions of electrical resistance are
- A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply