| ⇦ | 
| ⇨ |
In a nuclear reactor, the number of U²³⁵ nuclei undergoing fissions per second is 4×10²⁰. If the energy released per fission is 250 MeV, then the total energy released in 10 h is (1 eV=1.6×10⁻¹⁹ J)
Options
(a) 576×10⁶ J
(b) 576×10¹² J
(c) 576×10¹⁵ J
(d) 576×10¹⁸ J
Correct Answer:
576×10¹² J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - For CE transistor amplifier, the audio signal voltage across the collector resistance
- A police jeep is chasing a culprit going on a motorbike.The motorbike crosses
- A block slides from an inclination of 45°.If it takes time twice
- The velocity of image when object and mirror both are moving towards each other
- A ship A is moving westwards with a speed of 10 km/h and a ship B 100 km
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For CE transistor amplifier, the audio signal voltage across the collector resistance
- A police jeep is chasing a culprit going on a motorbike.The motorbike crosses
- A block slides from an inclination of 45°.If it takes time twice
- The velocity of image when object and mirror both are moving towards each other
- A ship A is moving westwards with a speed of 10 km/h and a ship B 100 km
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply