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In a common emitter (CE) amplifier having a voltage gain G, the transistor used has transconductance 0.03 mho and current gain 25. If the above transistor is replaced with another one with transconductance 0.02 mho and current gain 20, the voltage gain will be
Options
(a) 1.5 G
(b) 1/3 G
(c) 5/4 G
(d) 2/3 G
Correct Answer:
2/3 G
Explanation:
Voltage gain ∆ᵥ = β Rₒᵤₜ / Rᵢₙ
G = 25 Rₒᵤₜ / Rᵢₙ ….(i)
Transconductance gₘ = β / Rᵢₙ
Rᵢₙ = β / gₘ = 25 / 0.03
Puttin g this value of Rᵢₙ in eqn.(i)
G = 25 Rₒᵤₜ / 25 x 0.03 …(ii)
G’ = 20 Rₒᵤₜ / 20 x 0.02 …(iii)
From eqs. (ii) and (iii)
Voltage gain of new transistor G’ = 2/3 G
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A thermoelectric refrigerator works on
- The inductive reactance of an inductor of 1/π henry at 50 Hz frequency is
- Application of a forward bias to a P-N junction
- Which of the following is not a transverse wave?
- A coil of 40 henry inductance is connected in series with a resistance of 8 ohm
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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