⇦ | ![]() | ⇨ |
In a buffer solution containing equal concentration of B⁻ and HB, the Kb for B⁻ is 10⁻¹⁰.The pH of buffer solution is
Options
(a) 10
(b) 7
(c) 6
(d) 4
Correct Answer:
4
Explanation:
We know, pOH = pK(b) + log{[B⁻]/[HB]},
Since, [B⁻] = [HB] (given).
Therefore pOH = pK(b) ⇒ pOH = 10,
Therefore pH = 14 – 10 = 4.
Related Questions:
- The solubility of I₂ increases in water in the presence of
- How much energy is released when 6 moles of octane is burnt in air
- The heat of neutralization is the highest in the following case
- What is the product of the reduction of a carboxylic ester using a reagent
- In Friedel-Craft’s alkylation, besides AlCl₃ the other reactants are
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply