| ⇦ | 
| ⇨ |
In a buffer solution containing equal concentration of B⁻ and HB, the Kb for B⁻ is 10⁻¹⁰.The pH of buffer solution is
Options
(a) 10
(b) 7
(c) 6
(d) 4
Correct Answer:
4
Explanation:
We know, pOH = pK(b) + log{[B⁻]/[HB]},
Since, [B⁻] = [HB] (given).
Therefore pOH = pK(b) ⇒ pOH = 10,
Therefore pH = 14 – 10 = 4.
Related Questions: - Higher percentage of carbon is found in
- Copper occurs naturally as Cu-63 and Cu-65. Given Atomic Weight
- The structure of XeOF₄ is
- At what temperature will the volume of gas becomes 2x, if volume
- For azimuthal quantum number l= 3,the maximum number of electrons will be
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Higher percentage of carbon is found in
- Copper occurs naturally as Cu-63 and Cu-65. Given Atomic Weight
- The structure of XeOF₄ is
- At what temperature will the volume of gas becomes 2x, if volume
- For azimuthal quantum number l= 3,the maximum number of electrons will be
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply