If the dipole moment of a short bar magnet is 1.25 A-m², the magnetic field on its

⇦

⇨

If the dipole moment of a short bar magnet is 1.25 A-m², the magnetic field on its axis at a distance of 0.5 m from the centre of the magnet is

Options

(a) 1×10⁻⁴ NA⁻¹ m⁻¹
(b) 2×10⁻⁶NA⁻¹ m⁻¹
(c) 4×10⁻²NA⁻¹ m⁻¹
(d) 6.64×10⁻⁸NA⁻¹ m⁻¹

Correct Answer:

2×10⁻⁶NA⁻¹ m⁻¹

Explanation:

The magnetic field at a point on the axis of a bar magnet is, B = 2μ₀M / 4πr³

= 10⁻⁷ × [(2×1.25) / (0.5)³] = 2 x 10⁻⁶ NA⁻¹ m⁻¹

Related Questions:

1. Which of the following atoms has the lowest ionisation potential?
2. The focal lengths of a converging lens are fᵥ and fᵣ for violet and red lights
3. A proton carrying 1 MeV kinetic energy is moving in a circular path of radius
4. The radius of a planet is twice the radius of earth. Both have almost
5. When the disc rotates with uniform angulr velocity.Which of the following is not true?

Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends