MENU

If the dipole moment of a short bar magnet is 1.25 A-m², the magnetic field on its

If The Dipole Moment Of A Short Bar Magnet Is Physics Question

If the dipole moment of a short bar magnet is 1.25 A-m², the magnetic field on its axis at a distance of 0.5 m from the centre of the magnet is

Options

(a) 1×10⁻⁴ NA⁻¹ m⁻¹
(b) 2×10⁻⁶NA⁻¹ m⁻¹
(c) 4×10⁻²NA⁻¹ m⁻¹
(d) 6.64×10⁻⁸NA⁻¹ m⁻¹

Correct Answer:

2×10⁻⁶NA⁻¹ m⁻¹

Explanation:

The magnetic field at a point on the axis of a bar magnet is, B = 2μ₀M / 4πr³

= 10⁻⁷ × [(2×1.25) / (0.5)³] = 2 x 10⁻⁶ NA⁻¹ m⁻¹

Related Questions:

  1. The unit of permitivity of free space, ε₀ is
  2. A particle with total energy E is moving in a potential energy region U(x)
  3. During an adiabatic process, the pressure of a gas is found to be proportional
  4. A nucleus with mass number 220 initially at rest emits an α-particle. If the Q-value
  5. Three objects A,B and C are kept in a straight line on a frictionless horizontal surface

Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*