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If the dimensions of a physical quantity are givenby Mᵃ Lᵇ Tᶜ, then the physical quantity will be:
Options
(a) Velocity if a= 1, b = 0, c = – 1
(b) Acceleration if a= 1, b = 1, c = – 2
(c) Force if a = 0, b = – 1, c = – 2
(d) Pressure if a = 1, b= – 1,c = – 2
Correct Answer:
Pressure if a = 1, b= – 1,c = – 2
Explanation:
Pressure = MLT⁻² / L² = ML⁻¹T⁻²
⇒ a= 1, b= -1, c= -2.
Related Questions: - A,B and C are voltmeters of resistance R, 1.5 R and 3R respectively, as shown
- The width of the diffraction band varies
- The sum of the magnitudes of two forces acting at a point is 16 N
- A body of mass 1.0 kg is falling with an acceleration of 10 ms⁻².
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Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A,B and C are voltmeters of resistance R, 1.5 R and 3R respectively, as shown
- The width of the diffraction band varies
- The sum of the magnitudes of two forces acting at a point is 16 N
- A body of mass 1.0 kg is falling with an acceleration of 10 ms⁻².
- The electric potential at a point in free space due to a charge Q coulomb is Q x 10¹¹ v
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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