| ⇦ | 
| ⇨ |
If principal quantum number n=4, the total number of orbitals having l=3 is
Options
(a) 3
(b) 7
(c) 5
(d) 9
Correct Answer:
7
Explanation:
For n= 4, /= 3 (f-subshell) no. of values ,= 2/ + 1 = 7 values. No. of orbitals in f-subshell is 7.
Related Questions: - Which of the following is dihydric alcohol
- The unit of second order reaction rate constant is
- Which of the following transition element shows the highest oxidation state
- Which one of the following is tridentate ligand
- The type of hybridisation of boron in diboron is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is dihydric alcohol
- The unit of second order reaction rate constant is
- Which of the following transition element shows the highest oxidation state
- Which one of the following is tridentate ligand
- The type of hybridisation of boron in diboron is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply