| ⇦ | 
| ⇨ |
If principal quantum number n=4, the total number of orbitals having l=3 is
Options
(a) 3
(b) 7
(c) 5
(d) 9
Correct Answer:
7
Explanation:
For n= 4, /= 3 (f-subshell) no. of values ,= 2/ + 1 = 7 values. No. of orbitals in f-subshell is 7.
Related Questions: - Nitrobenzene combines with hydrogen in the presence of platinum to yield
- The nucleic acid base having two possible binding sites is
- Two moles of an ideal gas expand spontaneously into a vacuum. The work done is
- If 900 J/g of heat is exchanged at boiling point of water, then what is increase
- K₃Fe(CN)₆ + e⁻ → K₄Fe(CN)₆ is known as
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Nitrobenzene combines with hydrogen in the presence of platinum to yield
- The nucleic acid base having two possible binding sites is
- Two moles of an ideal gas expand spontaneously into a vacuum. The work done is
- If 900 J/g of heat is exchanged at boiling point of water, then what is increase
- K₃Fe(CN)₆ + e⁻ → K₄Fe(CN)₆ is known as
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply