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If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton and neutron respectively in units of u (1u = 931.5 MeV/c) and BE represents its bonding energy in MeV, then
Options
(a) M(A, Z) = ZMₚ + (A – Z)Mₙ – BE/c²
(b) M(A, Z) = ZMₚ + (A – Z)Mₙ + BE
(c) M(A, Z) = ZMₚ + (A – Z)Mₙ – BE
(d) M(A, Z) = ZMₚ + (A – Z)Mₙ + BE/c²
Correct Answer:
M(A, Z) = ZMₚ + (A – Z)Mₙ – BE/c²
Explanation:
Mass defect = ZMₚ + (A – Z)Mₙ – M(A – Z)
or, B.E. / c² = ZMₚ + (A – Z)Mₙ – M(A – Z)
M(A – Z) = ZMₚ + (A – Z)Mₙ – B.E. / c²
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ionization energy of Li⁺⁺ is equal to
- Energy stored in the coil of a self inductance 40 mH carrying a steady current of 2A
- In Young’s double slit experiment, the ratio of maximum and minimum intensities
- Magnetism of a magnet is due to
- The resistance of a wire is 5 ohm at 50° C and 6 ohm at 100° C. The resistance
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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