| ⇦ | 
| ⇨ |
If a spring of spring constant k stretched by a length x under tension T, the energy stored is
Options
(a) 2k/T²
(b) 2T²/k
(c) T²/2k
(d) 2T/k²
Correct Answer:
T²/2k
Explanation:
Energy stored in the spring, U = (1/2).kx²
Since T = kx, .·. U = (1/2) k (T/k)² = T²/2k.
Related Questions: - Which of the following physical quantities has neither dimensions nor unit
- The molar specific heats of an ideal gas at constant pressure and volume are denoted
- A,B and C are voltmeters of resistance R, 1.5 R and 3R respectively, as shown
- The phase difference between the instantaneous velocity and acceleration of a particle
- Electric potential at any point is V= -5x +3y + √(15) z. Then the magnitude of electric
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following physical quantities has neither dimensions nor unit
- The molar specific heats of an ideal gas at constant pressure and volume are denoted
- A,B and C are voltmeters of resistance R, 1.5 R and 3R respectively, as shown
- The phase difference between the instantaneous velocity and acceleration of a particle
- Electric potential at any point is V= -5x +3y + √(15) z. Then the magnitude of electric
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply