If a charge in current of 0.01 A in one coil produces a change in magnetic flux of 1.2 x 10⁻² Wb in the outer coil, then the mutual inductance of the coils in henry is
Options
(a) 0
(b) 1.2
(c) 3
(d) 1.5
Correct Answer:
1.2
Explanation:
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Magenetic flux=LXdI/dt
flux=2 x 10^(-2)
current flown in 1 sec is 0.001 amppere
ie,dI/dt = 0.01A
=>2 x 10^(-2) = L x 0.001
=>L = 2 x 10^(-2)/0.001
=>L = 2H