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Hydrogen atom in ground state is excited by a monochrmatic radiation of λ=975 Å. Number of spectral lines in the resulting spectrum emitted will be
Options
(a) 3
(b) 2
(c) 6
(d) 10
Correct Answer:
6
Explanation:
For the λ=975 Å
1 / λ = R [(1/n₁²) – (1/n₂²)]
where R is the Rydberg constant
Solving we get n₂ = n = 4 (Since, n₁ = 1 ground state)
Therefore number of spectral lines = n(n – 1) / 2 = 4(4 – 1) / 2 = 6.
Related Questions: - The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
- Which of the following phenomena does not show the wavenature of light?
- After 300 days, the activity of a radioactive sample is 5000 dps
- When three identical bulbs of 60 W-200 V rating are connected in series to a 200 V
- Find out the e.m.f. produced when the current changes from 0 to 1 A in 10 sec.
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
- Which of the following phenomena does not show the wavenature of light?
- After 300 days, the activity of a radioactive sample is 5000 dps
- When three identical bulbs of 60 W-200 V rating are connected in series to a 200 V
- Find out the e.m.f. produced when the current changes from 0 to 1 A in 10 sec.
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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