| ⇦ | 
| ⇨ |
Hydrogen atom in ground state is excited by a monochrmatic radiation of λ=975 Å. Number of spectral lines in the resulting spectrum emitted will be
Options
(a) 3
(b) 2
(c) 6
(d) 10
Correct Answer:
6
Explanation:
For the λ=975 Å
1 / λ = R [(1/n₁²) – (1/n₂²)]
where R is the Rydberg constant
Solving we get n₂ = n = 4 (Since, n₁ = 1 ground state)
Therefore number of spectral lines = n(n – 1) / 2 = 4(4 – 1) / 2 = 6.
Related Questions: - In which process, the P-V indicator diagram is a straight line parallel to volume
- Water flows through a pipe. The area of cross-section at one place A₁=10 cm²,
- Light of wavelength λ from a point source falls on a small circular obstacle
- Three objects coloured black, gray and white can withstand hostile conditions upto 2800⁰C.
- The relationship between decay constant λ and half-life T of a radioactive substance is
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In which process, the P-V indicator diagram is a straight line parallel to volume
- Water flows through a pipe. The area of cross-section at one place A₁=10 cm²,
- Light of wavelength λ from a point source falls on a small circular obstacle
- Three objects coloured black, gray and white can withstand hostile conditions upto 2800⁰C.
- The relationship between decay constant λ and half-life T of a radioactive substance is
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply