How much work is required to carry a 6 μC charge from the negative terminal

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How much work is required to carry a 6 μC charge from the negative terminal to the positive terminal of a 9V battery?

Options

(a) 54×10⁻³ J
(b) 54×10⁻⁶ J
(c) 54×10⁻¹⁹ J
(d) 54×10⁻¹² J

Correct Answer:

54×10⁻⁶ J

Explanation:

Work done = q × V = (6 × 10⁻⁶) × 6 = 54 × 10⁻⁶ J

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Topics: Current Electricity (136)
Subject: Physics (2479)

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