| ⇦ | 
| ⇨ |
Heating a mixture of sodium benzoate and soda lime gives
Options
(a) toluene
(b) aniline
(c) benzene
(d) none of these
Correct Answer:
benzene
Explanation:
C₆H₅ – COONa + NaOH → C₆H₆ + Na₂CO₃ .
Sodium benzoate on heating with sodalime undergoes decarboxylation reaction giving benzene.
Related Questions: - Copper occurs naturally as Cu-63 and Cu-65. Given Atomic Weight
- How many coulombs are required for the oxidation of 1 mole H₂O to O₂
- Which one of the following is produced when acetone is saturated with HCl gas
- What is the formula of bleaching powder
- What is the composition of tear gas
Topics: Hydrocarbons
(84)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Copper occurs naturally as Cu-63 and Cu-65. Given Atomic Weight
- How many coulombs are required for the oxidation of 1 mole H₂O to O₂
- Which one of the following is produced when acetone is saturated with HCl gas
- What is the formula of bleaching powder
- What is the composition of tear gas
Topics: Hydrocarbons (84)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply