| ⇦ |
| ⇨ |
Heat of formation of H₂O(g) at 25⁰C is -243 kJ,ΔE for the reaction H₂(g) + 1/2 O₂(g) → H₂O(g) at 25⁰C is
Options
(a) -243 kJ
(b) -241.8 kJ
(c) 241.8 kJ
(d) 243 kJ
Correct Answer:
-241.8 kJ
Explanation:
H₂(g) + 1/2 O₂(g) → H₂O(g),
ΔHf = -243 kJ, ΔH = ΔE + Δn(g)RT,
where ΔH = enthalpy change of reaction = -243 kJ,
ΔE = internal energy change of reaction, Δn(g) = number of gaseous product – number of gaseous reactant = 1-(1+ 1/2) = – 1/2. ⇒ ΔE = ΔH – Δn(g)RT = -243000 + 0.5 x 8.314 x 298 = -241.76 kJ.
Related Questions: - Which of the following is the most electronegative element?
- Which of the following does not contain aluminium
- Smallest wavelength occurs for
- Which one of the following is an example of heterogenous catalysis
- Which of the following is true about ClO₂
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is the most electronegative element?
- Which of the following does not contain aluminium
- Smallest wavelength occurs for
- Which one of the following is an example of heterogenous catalysis
- Which of the following is true about ClO₂
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply