| ⇦ | 
| ⇨ |
Four indentical thin rods each of mass M and length l, form a square frame. Momentum of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is:
Options
(a) 2/3 MI²
(b) 13/3 MI²
(c) 1/3 MI²
(d) 4/3 MI²
Correct Answer:
4/3 MI²
Explanation:
Moment of inertia of oa thin rod of length l about an axis passing through centre and perpendicular to the rod = 1/12 MI².
Thus, moment of inertia of the frame.
MI² / 12 + MI² / 4 = 4 MI² / 12 = MI² / 3
Total M.I. = 4/3 MI²
Related Questions:
- Photons of energy 6 eV are incident on a metal surface whose work function is 4 eV.
- Imagine a light planet revolving around a very massive star in a circular
- On adjusting the P-N junction diode in forward bias,
- A rod of weight W is supported by two parallel knife edge A and B
- A pan is suspended from a steel wire. Weights are slowly put on the pan
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply