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Equivalent weight of KMnO₄ in basic medium is (mol.wt. of KMnO₄ = 158)
Options
(a) 31.5
(b) 52.67
(c) 79
(d) 158
Correct Answer:
52.67
Explanation:
MnO₄⁻ + 2H₂O + 3e⁻ → MnO₂ + 4OH⁻
Equivalent weight = molecular weight / 3.
The oxidation number changes from +7 to +4. so , Equivalent weight = 158/3 = 52.67.
Related Questions: - The common oxidation state shown by lanthanides in their compounds is
- 0.765 gm of acid gives 0.55 g of CO₂ and 0.12 g of H₂O.Then find the ratio
- In which of the following molecules is hydrogen bridge bond present
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Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The common oxidation state shown by lanthanides in their compounds is
- 0.765 gm of acid gives 0.55 g of CO₂ and 0.12 g of H₂O.Then find the ratio
- In which of the following molecules is hydrogen bridge bond present
- The property,which can be classified as an intensive property, is
- The inert gas abundantly found in atmosphere is
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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