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Equivalent weight of KMnO₄ in basic medium is (mol.wt. of KMnO₄ = 158)
Options
(a) 31.5
(b) 52.67
(c) 79
(d) 158
Correct Answer:
52.67
Explanation:
MnO₄⁻ + 2H₂O + 3e⁻ → MnO₂ + 4OH⁻
Equivalent weight = molecular weight / 3.
The oxidation number changes from +7 to +4. so , Equivalent weight = 158/3 = 52.67.
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Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
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