| ⇦ |
| ⇨ |
Energy stored in the coil of a self inductance 40 mH carrying a steady current of 2A is
Options
(a) 0.8 J
(b) 0.08 J
(c) 8 J
(d) 80 J
Correct Answer:
0.08 J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A nucleus ᵐₙ X emits one α- particle and two β- particles. The resulting nucleus is
- If the self inductance of 500 turn coil is 125 mH, then the self inductance
- If both the resistance and the inductance in an LR AC series circuit are doubled
- A stone tied to the end of a string of 1 m long is whirled in a horizontal circle
- In stretching a spring by 2 cm, energy stored is given by U. Had is been stretched
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A nucleus ᵐₙ X emits one α- particle and two β- particles. The resulting nucleus is
- If the self inductance of 500 turn coil is 125 mH, then the self inductance
- If both the resistance and the inductance in an LR AC series circuit are doubled
- A stone tied to the end of a string of 1 m long is whirled in a horizontal circle
- In stretching a spring by 2 cm, energy stored is given by U. Had is been stretched
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply