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Energy of photon whose frequency is 10¹² MHz will be
Options
(a) 4.14×10³ KeV
(b) 4.14×10² eV
(c) 4.14×10³ MeV
(d) 4.14×10³ eV
Correct Answer:
4.14×10³ eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bulbs 40 watt and 60 watt and rated voltage 240 V are connected in series
- Radius of first orbit of the electron in a hydrogen atom is 0.53 Å. So the radius
- If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum
- A current is flowing through resistance. A potential difference of 120 V
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Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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