| ⇦ | 
| ⇨ |
Decreasing order of stability of O₂ , O₂⁻ , O₂⁺ and O₂²⁻ is
Options
(a) O₂²⁻ > O₂⁻ > O₂ >O₂⁺
(b) O₂> O₂⁺ > O₂²⁻ > O₂⁻
(c) O₂⁻ > O₂²⁻ > O₂⁺ >O₂
(d) O₂⁺ > O₂ > O₂⁻ > O₂²⁻
Correct Answer:
O₂⁺ > O₂ > O₂⁻ > O₂²⁻
Explanation:
According to molecular orbital theory as bond order decreases stability of the molecule decreases
Bond order =1/2 (N(b)-N(a))
Bond order for O₂⁺=1/2 (10-5)=2.5
Bond order for O₂=1/2 (10-6)=2
Bond order for O₂⁻=1/2 (10-7)=1.5
Bond order for O₂²⁻=1/2 (10-8)=1.0
hence the correct order is
O₂⁺ > O₂ > O₂⁻> O₂²⁻
Related Questions: - Which of the following is correct option for free expansion of an ideal gas
- Which reagent can be used for the alkylation of aromatic nitro compounds
- The sum of coordination number and oxidation number of the metal M in the complex
- Which of the following pairs has both members from the same group of periodic
- If 2 g of aluminium is treated, first with excess of dilute H₂SO₄ and then
Topics: Chemical Bonding and Molecular Structure
(86)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is correct option for free expansion of an ideal gas
- Which reagent can be used for the alkylation of aromatic nitro compounds
- The sum of coordination number and oxidation number of the metal M in the complex
- Which of the following pairs has both members from the same group of periodic
- If 2 g of aluminium is treated, first with excess of dilute H₂SO₄ and then
Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply