Decreasing order of stability of O₂ , O₂⁻ , O₂⁺ and O₂²⁻ is

⇦

⇨

Decreasing order of stability of O₂ , O₂⁻ , O₂⁺ and O₂²⁻ is

Options

(a) O₂²⁻ > O₂⁻ > O₂ >O₂⁺
(b) O₂> O₂⁺ > O₂²⁻ > O₂⁻
(c) O₂⁻ > O₂²⁻ > O₂⁺ >O₂
(d) O₂⁺ > O₂ > O₂⁻ > O₂²⁻

Correct Answer:

O₂⁺ > O₂ > O₂⁻ > O₂²⁻

Explanation:

According to molecular orbital theory as bond order decreases stability of the molecule decreases
Bond order =1/2 (N(b)-N(a))
Bond order for O₂⁺=1/2 (10-5)=2.5
Bond order for O₂=1/2 (10-6)=2
Bond order for O₂⁻=1/2 (10-7)=1.5
Bond order for O₂²⁻=1/2 (10-8)=1.0
hence the correct order is
O₂⁺ > O₂ > O₂⁻> O₂²⁻

Related Questions:

1. Enzymes actually
2. Order of reaction is decided by
3. The C – C bond length in ethane is
4. Ethanol and dimethyl ether have same empirical formula but ethanol has higher boiling
5. A detergent has which of the following group attached to the terminal of a long carbon

Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends