⇦ | ⇨ |
Decreasing order of stability of O₂ , O₂⁻ , O₂⁺ and O₂²⁻ is
Options
(a) O₂²⁻ > O₂⁻ > O₂ >O₂⁺
(b) O₂> O₂⁺ > O₂²⁻ > O₂⁻
(c) O₂⁻ > O₂²⁻ > O₂⁺ >O₂
(d) O₂⁺ > O₂ > O₂⁻ > O₂²⁻
Correct Answer:
O₂⁺ > O₂ > O₂⁻ > O₂²⁻
Explanation:
According to molecular orbital theory as bond order decreases stability of the molecule decreases
Bond order =1/2 (N(b)-N(a))
Bond order for O₂⁺=1/2 (10-5)=2.5
Bond order for O₂=1/2 (10-6)=2
Bond order for O₂⁻=1/2 (10-7)=1.5
Bond order for O₂²⁻=1/2 (10-8)=1.0
hence the correct order is
O₂⁺ > O₂ > O₂⁻> O₂²⁻
Related Questions: - A certain current liberated 0.504 g of hydrogen in 2 hours. How many grams
- Aluminium (III) chloride forms a dimer because aluminium
- The boiling point of heavy water is
- The difference between ΔH and ΔE at 300 K for the reaction
- The strained tetracyclic alkane is isomerized thermally to the cyclic alkene.
Topics: Chemical Bonding and Molecular Structure
(86)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A certain current liberated 0.504 g of hydrogen in 2 hours. How many grams
- Aluminium (III) chloride forms a dimer because aluminium
- The boiling point of heavy water is
- The difference between ΔH and ΔE at 300 K for the reaction
- The strained tetracyclic alkane is isomerized thermally to the cyclic alkene.
Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply