Decreasing order of stability of O₂ , O₂⁻ , O₂⁺ and O₂²⁻ is

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Decreasing order of stability of O₂ , O₂⁻ , O₂⁺ and O₂²⁻ is

Options

(a) O₂²⁻ > O₂⁻ > O₂ >O₂⁺
(b) O₂> O₂⁺ > O₂²⁻ > O₂⁻
(c) O₂⁻ > O₂²⁻ > O₂⁺ >O₂
(d) O₂⁺ > O₂ > O₂⁻ > O₂²⁻

Correct Answer:

O₂⁺ > O₂ > O₂⁻ > O₂²⁻

Explanation:

According to molecular orbital theory as bond order decreases stability of the molecule decreases
Bond order =1/2 (N(b)-N(a))
Bond order for O₂⁺=1/2 (10-5)=2.5
Bond order for O₂=1/2 (10-6)=2
Bond order for O₂⁻=1/2 (10-7)=1.5
Bond order for O₂²⁻=1/2 (10-8)=1.0
hence the correct order is
O₂⁺ > O₂ > O₂⁻> O₂²⁻

Related Questions:

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3. What is formed when formaldehyde reacts with KOH
4. Assuming complete ionisation same moles of which of the following compounds
5. Which of the following transition element shows the highest oxidation state

Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)

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