| ⇦ | 
| ⇨ |
Considering entropy (S) as a thermodynamic parameter, the criterion for the spontaneity of any process is
Options
(a) ΔS system + ΔS surroundings > 0
(b) ΔS system – ΔS surroundings > 0
(c) ΔS system > 0 only
(d) ΔS surroundings > 0 only
Correct Answer:
ΔS system + ΔS surroundings > 0
Explanation:
ΔS = Rln V₂/V₁,
Here the volume of gas increases from V₁ to V₂ at consant temperature T. The total increase in entropy of the system and its surroundings during the spontaneous process of expansion considered above is, thus R ln (V₂/V₁).Since V₂ > V₁, it is obvious that the spontaneous (irreversible) isothermal expansion of a gas is accompanied by a increase in the entropy of the system and its surroundings considered together.
ΔS(sys) + ΔS(surr > 0.
Related Questions: - The polymer used in orthopaedic devices and in controlled drug release is
- Planar structure is shown by
- In the Kjeldahl’s method for estimation of nitrogen present in a soil sample
- Para and ortho-hydrogen differ in
- If principal quantum number n=4, the total number of orbitals having l=3 is
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The polymer used in orthopaedic devices and in controlled drug release is
- Planar structure is shown by
- In the Kjeldahl’s method for estimation of nitrogen present in a soil sample
- Para and ortho-hydrogen differ in
- If principal quantum number n=4, the total number of orbitals having l=3 is
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply