Complete oxidation of 1 gm molecule of glucose gives rise to

⇦

⇨

Complete oxidation of 1 gm molecule of glucose gives rise to

Options

(a) 68,60,000 cal
(b) 6,86,000 cal
(c) 68,600 cal
(d) 6,800 cal

Correct Answer:

6,86,000 cal

Explanation:

1 molecule of glucose yields 56kcal/2ATP in anaerobic respiration and 686000 calories (686 kcal)/total of 38 ATP in aerobic respiration.

Related Questions:

1. Hypothalamus does not control
2. Devices for self-pollination are
3. Below Image is the floral formula of
4. In prokaryotes, the genetic material is
5. Match the disease with the appropriate pathogen/prevention/ treatment

Topics: Respiration in Plants (184)
Subject: Biology (4253)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends