| ⇦ | 
| ⇨ |
Calcination is used in metallurgy to remove
Options
(a) CO₂ and H₂S
(b) H₂O and SiO₂
(c) H₂O and H₂S
(d) H₂O and CO₂
Correct Answer:
H₂O and CO₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which of the following will exhibit maximum ionic conductivity?
- When carbon monoxide is passed over solid caustic soda heated to 200▫ C it forms
- If Ksp for HgSO₄ is 6.4 x 10⁻⁵, then solubility of the salt is
- The IUPAC name of CH₂=CHCH(CH₃)₂ is
- Which of the following is correct relationship
Topics: Surface Chemistry and Isolation of Elements
(88)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following will exhibit maximum ionic conductivity?
- When carbon monoxide is passed over solid caustic soda heated to 200▫ C it forms
- If Ksp for HgSO₄ is 6.4 x 10⁻⁵, then solubility of the salt is
- The IUPAC name of CH₂=CHCH(CH₃)₂ is
- Which of the following is correct relationship
Topics: Surface Chemistry and Isolation of Elements (88)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply