| ⇦ | 
| ⇨ |
By which one of the following compounds both CH₄ and CH₃ – CH₃ can be prepared in one step
Options
(a) CH₃ I
(b) CH₃ OH
(c) CH₃ CH₂I
(d) C₂H₅OH
Correct Answer:
CH₃ I
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Dumas method is used for the estimation of
- The sum of coordination number and oxidation number of the metal M in the complex
- Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl has pH 9.25 . Then fine out pKb of NH₄OH
- Four successive members of the first row transition elements are listed below
- In crystals of which one of the following ionic compounds would you expect maximum
Topics: Hydrocarbons
(84)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Dumas method is used for the estimation of
- The sum of coordination number and oxidation number of the metal M in the complex
- Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl has pH 9.25 . Then fine out pKb of NH₄OH
- Four successive members of the first row transition elements are listed below
- In crystals of which one of the following ionic compounds would you expect maximum
Topics: Hydrocarbons (84)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply