| ⇦ | 
| ⇨ |
An organic compound contains 49.3% carbon, 6.84% hydrogen and its vapour density is 73. Molecular formula of the compound is
Options
(a) C₃H₈O₂
(b) C₃H₁₀O
(c) C₆H₉O
(d) C₆H₁₀O₄
Correct Answer:
C₆H₁₀O₄
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A sample of chloroform before being used as an anaesthetic agent is tested by
- The compound used in enrichment for uranium for nuclear power plant is
- Vapour density of a gas is 22. What is its molecular weight
- The most basic amine among the following is
- Octane number can be changed by
Topics: Basic Principles of Organic Chemistry
(124)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A sample of chloroform before being used as an anaesthetic agent is tested by
- The compound used in enrichment for uranium for nuclear power plant is
- Vapour density of a gas is 22. What is its molecular weight
- The most basic amine among the following is
- Octane number can be changed by
Topics: Basic Principles of Organic Chemistry (124)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply