An open pipe resonates with a tuning fork of frequency 500 Hz. It is observed that two successive nodes are formed at distances 16 cm and 46 cm from the open end. The speed of sound in air in the pipe is

Options

(a) 230 m/s
(b) 300 m/s
(c) 320 m/s
(d) 360 m/s

Correct Answer:

300 m/s

Explanation:

Two successive modes are separated by λ/2. λ/2 = (46-16)=30 λ=60 cm=0.6 m v=nλ=500×0.6=300 m/s.