An ideal gas is compressed to half its initial volume by means of several processes. Which of the progress results in the maximum work done on the gas?

Options

(a) Isochoric
(b) Isothermal
(c) Adiabatic
(d) Isobaric

Correct Answer:

Adiabatic

Explanation:

Since area under the curve is maximum for adiabatic process so, work done (W = PdV) on the gas will be maximum for adiabatic process.