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An ideal gas is compressed to half its initial volume by means of several processes. Which of the progress results in the maximum work done on the gas?
Options
(a) Isochoric
(b) Isothermal
(c) Adiabatic
(d) Isobaric
Correct Answer:
Adiabatic
Explanation:
Since area under the curve is maximum for adiabatic process so, work done (W = PdV) on the gas will be maximum for adiabatic process.
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A coin placed on a rotating turn table just slips,if it is placed at a distance
- The numebr 0 (zero) is required for
- A nucleus of uranium decays at rest into nuclei of thrrium and helium. Then
- If the pressure of gas is increased from 1.01×10⁵ Pa to 1.165×10⁵ Pa and volume
- A photosensitive metallic surface has work function, hν₀. If photons of energy
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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