An electric dipole of length 1 cm is placed with the axis making an angle of 30⁰

An electric dipole of length 1 cm is placed with the axis making an angle of 30⁰ to an electric field of strength 10⁴ NC⁻¹. If it experiences a torque of Nm, the potential energy of the dipole is

Options

(a) 2.45 J
(b) 0.0245 J
(c) 245.0 J
(d) 24.5 J

Correct Answer:

24.5 J

Explanation:

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  • Torque=PE sin¢
    10√2= P×10^4 sin 30°
    P=2√2×10^-3

    U=PE cos 30°
    U=2√2×10^-3× 10^4 cos 30°
    =24.5 J

  • Torque=PE sin¢
    10√2= P×10^4 sin 30°
    P=2√2×10^-3

    U=PE cos 30°
    U=2√2×10^-3× 10^4 cos 30°
    =24.5 J

  • Torque=PE sin¢
    10√2= P×10^4 sin 30°
    P=2√2×10^-3

    U=PE cos 30°
    U=2√2×10^-3× 10^4 cos 30°
    =24.5 J

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