| ⇦ | 
| ⇨ |
An alternating voltage e=200s in100t is applied to a series combination of R= 30Ω and an inductor of 400 mH. The power factor of the circuit is
Options
(a) 0.01
(b) 0.05
(c) 0.042
(d) 0.6
Correct Answer:
0.6
Explanation:
Xʟ = Lω = 0.4 × 100 = 40
R = 30 Ω
.·. Power factor, cos ɸ = R / √(R² × Xʟ²) = 30 / √(R² × Xʟ²) = 30 / √(30² × 40²) = 0.6
Related Questions: - 1 curie is equal to
- When a mass M is attached to a spring of force constant K,
- The potential differences across the resistance, capacitance and inductance
- The potential energy of a weightless spring compressed by a distance D is proportional
- A common emitter amplifier gives an output of 3 V for an input of 0.01 V.
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 1 curie is equal to
- When a mass M is attached to a spring of force constant K,
- The potential differences across the resistance, capacitance and inductance
- The potential energy of a weightless spring compressed by a distance D is proportional
- A common emitter amplifier gives an output of 3 V for an input of 0.01 V.
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply