Navigate

An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus.

An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of

Options

(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm

Correct Answer:

10⁻¹² cm

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

AIEEE2004
admin:

Related Questions

  1. In which of the processes, does the internal energy of the system remain constant?
  2. Monochromatic light of frequency 6.0 x 10¹⁴ Hz is produced by a laser. The power emitted
  3. Calculate power output of ₉₂²³⁵U reactor, if it takes 30 days to use up 2 kg of fuel,
  4. In stretching a spring by 2 cm, energy stored is given by U. Had is been stretched
  5. An electron in potentiometer experiences a force 2.4×10⁻¹⁹N. The length of potentiometer